JAVA PROGRAM TO DEMONSTRATE THE PALINDROME PROGROM USING CLASSES AND OBJECT.

 

// JAVA PROGRAM TO DEMONSTRATE THE PALINDROME PROGROM USING CLASSES AND OBJECT.

class PalindromeExample {

    public static void main(String args[]) {

        int remainder, reversedNumber = 0, originalNumber;  // Declare variables for storing digits

       

        int numberToCheck = 454;  // The number to be checked for palindrome

       

        originalNumber = numberToCheck;  // Store the original number for later comparison

       

        // Reverse the digits of the number

        while (numberToCheck > 0) {

            remainder = numberToCheck % 10;  // Extract the last digit

            reversedNumber = (reversedNumber * 10) + remainder;  // Build the reversed number

            numberToCheck = numberToCheck / 10;  // Remove the last digit

        }

       

        // Check if the reversed number is equal to the original number

        if (originalNumber == reversedNumber) {

            System.out.println("The number is a palindrome.");  // Print if it's a palindrome

        } else {

            System.out.println("The number is not a palindrome.");  // Print if it's not a palindrome

        }

    }

}

OUTPUT:-

palindrome number

Explanation of the code:

• The code defines a class named PalindromeExample.

• Inside the class, there's the main method which serves as the entry point of the program.

• The program aims to check whether a given number (n initialized as 454) is a palindrome or not. A palindrome is a number that reads the same forwards and backwards.

• temp is used to store the original number so that we can compare it with the reversed number later.

• The while loop runs as long as the value of n is greater than 0. It extracts the last digit of n using the modulo operator %, adds it to the reverse (sum), and then removes the last digit from n by dividing it by 10.

• The reversed number is built digit by digit in the sum variable. For example, if n is 454, then sum becomes 010 + 4 = 4, then 410 + 5 = 45, then 45*10 + 4 = 454, which is the reverse of the original number.

• After the loop completes, the code checks whether the original number (temp) is equal to the reversed number (sum). If they are equal, the number is a palindrome and the program prints "palindrome number". If they are not equal, the number is not a palindrome and the program prints "not palindrome".

• In this specific example, since the original number (454) is the same as its reversed version (454), the program will print "palindrome number".